x^2=1320

Solution for x^2=1320 equation:

x^2=1320

We move all terms to the left:

x^2-(1320)=0

a = 1; b = 0; c = -1320;
Δ = b2-4ac
Δ = 02-4·1·(-1320)
Δ = 5280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5280}=\sqrt{16*330}=\sqrt{16}*\sqrt{330}=4\sqrt{330}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{330}}{2*1}=\frac{0-4\sqrt{330}}{2}
=-\frac{4\sqrt{330}}{2}
=-2\sqrt{330}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{330}}{2*1}=\frac{0+4\sqrt{330}}{2}
=\frac{4\sqrt{330}}{2}
=2\sqrt{330}
$